Show how an 8-bit number(A0A1A2A3A4A5A6A7) can be multiplied by a 4-bit number(A3A2A1A0) using four 2-bit multipliers and 6-bit adders?
Complete circuit diagram required and a truth table if any. Quantitiy of 2-bit multipliers to be used are only four and shall not exceed four whereas 6-bit adders, its up to you. Need until tomorrow